Numrat Binare
y-bartja 2y- për shkak te numrave binare Psh. 3=1+2*1 dmth. bartja është 1, 3=z, kurse 1 është pozita (x).
a2a1a0
b2b1b0
x4x3x2x1x0
0=a0b0=z0=x0+2y1
1=y1+a1b0+a0b1=z1=x1+2y2
2=y2+a2b0+a1b1+a0b2=z2=x2+2y2
3=y3+a2b1+a1b2=z3=x3+2y4
4=y4+a2b2=z4=x4+2y5
5=y5
c2c1c0
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x6x5x4x3x2x1x0
0=a0b0c0=z0=x0+2y1
1=y1+a1b0c0+a0b1c0+a0b0c1=z1=x1+2y2
2=y2+a2b0c0+a1b1c0+a1b0c1+a0b2c0+a0b1c1+a0b0c2=z2=x2+2y2
3=y3+a2b1c0+a2b0c1+a1b2c0+a1b1c1+a1b0c2+a0b2c1+a0b1c2=z3=x3+2y4
4=y4+a2b2c0+a2b1c1+a2b0c2+a1b2c1+a1b1c1+a0b2c2=z4=x4+2y5
5=y5+a2b2c1+a2b1c2+a1b2c2=z5=x5+2y6
6=y6+a2b2c2=z6=x6+2y7
7=y7
Sipas formules :
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120110
121100
121110
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1716051403021100
0=1∗0∗1=0=0+2∗0
1=0+0∗0∗0+1∗1∗1+1∗0∗1=1=1+2∗0
2=0+1∗0∗1+0∗1∗1+0∗0∗1+1∗1∗1+1∗1∗1+1∗0∗1=2=0+2∗1
3=1+1∗1∗1+1∗0∗1+0∗1∗1+0∗1∗1+0∗0∗1+1∗1∗1+1∗1∗1=4=0+2∗2
4=2+1∗1∗1+1∗1∗1+1∗0∗1+0∗1∗1+0∗1∗1+1∗1∗1=5=1+2∗2
5=2+1∗1∗1+1∗1∗1+0∗1∗1=4=0+2∗2
6=2+1∗1∗1=3=1+2∗1
7=1